How are the Even parity bit and Odd parity bit calculated in the 26A format?

Resolution:

Classifying where the even bits and odd bits are within a format is dependent on how the format was designed.  In the case of 26A, the first 13 bits are even and the last 13 bits are odd. 

Example:

Card number: 4095
Facility code bit set: 01100101
Card ID bit set: 0000111111111111
Wiegand calculated: 00110010100001111111111111

26A (Bit 1 = Even parity; Bits 2-9 = Site Code; Bits 10-25 = Badge ID; Bit 26 = Odd parity)
E SSSSSSSS BBBBBBBBBBBBBBBB O
0 01100101 0000111111111111 1

Parity Calculation: (Bit 1 = Even Parity; Bits 2-13 = Even bit set; Bits 14-25 = Odd bit set; Bit 26 =

Odd parity)
E SSSSSSSSBBBB BBBBBBBBBBBB O
0 011001010000 111111111111 1

Bits 2-13 has four “1” therefore the even parity bit 0, keeping the even bit set even, computes correctly over the first 13 bits.

Bits 14-25 has twelve “1” therefore the odd parity bit 1, making the odd bit set odd,  computes correctly over the last 13 bits.